ccna 200 301 syllabus of errors text to speech

ccna 200 301 syllabus of errors text to speech.From the above output, you can see that R2 declares the 192.168.2.0 network. Further use the "debugiprip" command on R1 to see if R2 has sent any routes over and you can see this output: "ignored vl packet from 12.1.1.2 (illegal version)? , suggesting that the version 1 packet received from R2 is not legal and R1 is ignoring the route updates sent by R2. How can R2 learn the routes on R1 when the versions on both ends do not match? Using the "showip protocols" command on R1 shows the following.Rlttshow ip protocolsDefault version control: sendversion 2, receive version 2 Interface SendRecvTriggeredRIPKey-chain Seriall/1 2 2 2 LoopbackO 2 2Use the "show ipprotocols" command on R2 to display the following: R2#show ip protocolsDefault version control: send version 1r receive any version Interface SendRecvTriggeredRIPKey-chain Seriall/0 LoopbackO 1 L 2 1 12 From the above output, you can find that R1 sends version 2, receive version 2; andAt this point, we have found the reason for the route asymmetry at both ends, so we can change R2's RIP protocol to version 2 as well.The command to configure the interface to send and receive R1P version is as followsThe following commands are used to configure the interface to send and receive R1P versionsR1(config)#int sl/1 R1(config-if)#ip rip receive version 12R2 (config)#int sl/0 R2(config-if)#ip rip sendversion 1 2