A. ip route 126.96.36.199 255.255.255.224 188.8.131.52
B. ip route 0.0.0.0 0.0.0.0 184.108.40.206
C. ip route 220.127.116.11 255.255.255.224 18.104.22.168 254
D. ip route 0.0.0.0 0.0.0.0 22.214.171.124
Correct Answer: C
ccna 200 301 syllabus meaning hindi to english.8. Solution: Question C asks: Which address and mask combination indicates the aggregation of EIGRP learned routes? This question examines the aggregation of routes and requires the aggregation of192.168.25.20/30, 192.168.25.16/30, 192.168.25.24/30, 192.168.25.28/30 aggregation, convert them to binary form, and then find the same number of bits to get 192.168.25.16/28,that is, 192.168. 25.16255.255.255.240.235 49.Solution: Question B asks "P addresses and routing protocols are configured as shown in the figure. the network administrator uses the "showipeigrpneighbors command on the Routerl router and loses out to the bottom of the topology in the figure. ask which statement is correct? When configured correctly, Routerl should have 2 EIGRP neighbors, but in the diagram there is only Router2 - a neighbor, Routed does not appear in the neighbor table, you can see from the diagram, on R3 only 192.16820 and 10Q0.0 are notifiedsegment, that is, only interface S1 and 10.0.4.0 are activated, while interface S0 is not activated, so it is not possible to establish a neighbor between R3 and R1. The solution is to add the 192.16830 network to Router3's routing process.\236Cl f J* Xp=i --OSPF***This chapter describes the characteristics of link-state routing protocols, OSPF features, terminology, packet types, neighbor relationship establishment, RID selection, DR and BDR election, metric value calculation, and basic and advanced OSPF configuration.Session 8.1 Link State Routing Protocols**
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