A. ip route 22.214.171.124 255.255.255.224 126.96.36.199
B. ip route 0.0.0.0 0.0.0.0 188.8.131.52
C. ip route 184.108.40.206 255.255.255.224 220.127.116.11 254
D. ip route 0.0.0.0 0.0.0.0 18.104.22.168
Correct Answer: C
ccna 200 301 bookshelves design.10.255.255.254o However 0 and 255 can also be legitimate host IDs. you just need to remember to make sure that the host bits are not all 0s or all 1s when identifying legitimate host addresses.Class B AddressesIn a Class B network address, the first 2 bytes are the network address and the last 2 bytes are the node address. Therefore, the format of a Class B address is as follows.addresses have the following format. Network. Network, Node. For example, in the IP address 172.16.30.56, 172.16 is the network address and 30.56 is the node address. The length of the network bits of a Class B address is 2 bytes, so up to 2] 6 different combinations can be created. However, since theHowever, because the designers of the interconnection network specified that the first two binary bits of the B-address are fixed at 1 and 0, only 14 binary bits can take on any value, resulting in a total of 16384 (214) Class B addresses. Class B addresses have 2 bytes for node addresses. Therefore, in a Class B network, there can be a total of 2, 2 (all. and all 1),65534 available node addresses.Valid Host IDs for Class B Networks Take a look at the following example to see how to calculate the valid IDs in a Class B network address To Host bit all 0 indicates a network address: 172.16.0.0o . Host bit all 1 indicates broadcast address: 172.16.255.255o140Valid host addresses are those numbered between the network address and the broadcast address: 172.16.0.1. 172.16.255.2540Class C AddressesIn a Class C network address, the first 3 bytes are the network address and the last 1 byte is the node address. Thus the format of a Class C address is as follows.
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