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ccna 200 301 bookshelf minecraft enchantment.= 64, 64+16 = 80, 80+16 = 96, 96+16= 112, 112+16= 128, 128+16= 144, 144+16 =160, 160+16= 176, 176+16= 192, 192+16 = 208, 208+16 = 224, 224+16 = 240o Following the broadcast address of each subnet? Appeal to valid host addresses? To answer the last two questions, you can look up the following table. The table lists the subnets, available hosts, and each subnetof the broadcast addresses. First write the addresses of all subnets according to the size of the address blocks (increments); then find the broadcast address of each subnet (always the value of the next available subnet minus 1); and finally fill in the host addresses. The following table summarizes all available subnet, host, and broadcast addresses for a Class C network using the mask 255.255.255.240.Subnet 0 16 32 48 64 80 96 112 128 144 160 176 192 208 224 240First host 1 17 33 49 65 81 97 113 129 145 161 177 193 209 225 241Last host 14 30 46 62 78 94 110 126 142 158 174 190 206 222 238 254Broadcast 15 31 47 63 79 95 111 127 143 159 175 191 207 223 239 2556.1 Basis of subnettingCisco knows that many people are not very good at . Calculate in increments of 16, so it is often difficult to determine valid subnet addresses, host addresses, and broadcast addresses when using the 255.255.255.240 mask for Class C networks. Therefore it is very wise to focus on learning this mask.Exercise Case #5C: 255.255.255.248(/29 )